Question

The sum of squares of diagonals of a rhombus is ……. the square of a side of the rhombus. *


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Answer 1

Answer:

rhombus

Step-by-step explanation:

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Answer 2

Answer:

A rhombus ABCD whose diagonals AC and BD intersect at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus bisect each other at right angles. ==> 4AB² = ( AC² + BD² ) .

Step-by-step explanation:

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