the sum of squares of first and product of other two os 154 in three consecutive numbers. find integers which is a multiple of 3
yashg1999:
please check your question again
is it wrong??
yes i think so
The question is correct
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Let the numbers be x,x+1 and x+2.
x²+(x+1)(x+2)=154
x²+x²+3x+2=154
2x²+3x-152=0
2x²-16x+19x-152=0
2x(x-8)+19(x-8)=0
(2x+19)(x-8)=0
x=-19/2 (not possible as number can't be in fractions)
x=8
The numbers are 8,9 and 10.
Of the above,9 is a multiple of 3.
x²+(x+1)(x+2)=154
x²+x²+3x+2=154
2x²+3x-152=0
2x²-16x+19x-152=0
2x(x-8)+19(x-8)=0
(2x+19)(x-8)=0
x=-19/2 (not possible as number can't be in fractions)
x=8
The numbers are 8,9 and 10.
Of the above,9 is a multiple of 3.
she was asking for integers .....so i was confused
ok
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here is your ans ....hope it will help you....
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