Math, asked by kakol, 6 months ago

) The sum of squares of first n natural numbers is given by n(n+1)(2n+1). Find the sum of squares of the first 10 natural numbers.

Answers

Answered by samanvithaurs

6

Answer:

2310

Step-by-step explanation:

n , n+1 ,2n+1

n is 10

:10 , 11 ,21

11 *21 is 231

110 * 21 is 2310

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