Question

The sum of squares of first n natural numbers is given by n(n+1)(2n+1) / 6. Find the sum of squares of the first 10 natural numbers.

question is from Class-7th please give me the correct answer NO FOOLISH ANSWER...​

Answer 1

Answer:

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Step-by-step explanation:

The sum of squares of first n natural numbers is given by 1/6(n+1)(2n+1) or 1/6(2n^3 + 3n^2 + n). The sum of squares of first n natural numbers is given by 1/6(n+1)(2n+1) or 1/6(2n3 + 3n2 + n). Find the sum of squares of the first 10 natural numbers.

Answer 2

Answer:

385

Step-by-step explanation:

the sum of squares of the first 10 natural no.s are 385