Question

The sum of squares of first n natural numbers is given by n(n+1)(2n+1)/6. Find the sum of squares of the 10 natural numbers.​

Answer 1

Answer:

The sum of squares of first 10 natural numbers [∴ put n=10]

= 1/6 (10)(10+1)(2 x 10+1)

= 1/6 x 10 x 11 x 21

= 385