Question

the sum of squares of the 2 numbers is 41 and their product is 4 find the difference between the two numbers​

Answer 1

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According to question, some data is given about two numbers, and we have to find their difference by using them.

GiveN:

• Sum of squares of the numbers = 41
• Product of the numbers = 4

To find their difference....?

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We know that the whole square of the difference of two numbers a and b is given by:

• (a - b)² = a² - 2ab + b²

We have the values of a² + b² and 2ab, if we consider the numbers be a and b. Let's plug in to get their difference.

⇛ a² + b² - 2ab

⇛ 41 - 2(4)

⇛ 41 - 8

⇛ 33

This can be given by:

⇛ (a - b)² = 33

⇛ a - b = $\pm$√33

Thus, the difference of the two numbers is +√33 or -√33 depending upon which of them is greater.

Answer 2

Step-by-step explanation:

Given : -

• the sum of squares of the 2 numbers is 41 . a² + b² = 41

• their product is 4 ab = 4

To Find : -

= a² + b² - 2ab

putting all values

= 41 - 2 × 4

= 33

According to the Question :

(a - b)² = 33

a - b = ± √33

Hence the difference between two numbers is √33