Question

The sum of squares of the first natural numbers is given by + 1 2 + 1 6 . Find the sum of squares of the first 1 natural numbers.​

Answer 1

Answer:

Put n=10 in the given expression

Sum of squares of first n natural numbers is given by

6

1

n(n+1)(2n+1)

Therefore, the sum of squares of the first 10 natural numbers

=

6

1

10(10+1)(2×10+1)

=

6

1

×10×11×21

=385

Hence, the sum of squares of the first 10 natural numbers is 385.