Question

The sum of squares of the first natural numbers is given by + 1 2 + 1 6 . Find the sum of squares of the first 12 natural numbers.​

Answer 1

Answer:

1² + 2² + 3² + 4² + ... + 12² = 650

Step-by-step explanation:

Sum of squares of first 'n' natural numbers is given by

n (n + 1) (2n + 1) / 6

Thus, the sum of squares of first 12 natural numbers =

12 × 13 × 25 / 6

= 650