Question

The sum of squares of three numbers is 398. The sum of their products, taken two at a time, is 379. Find the sum of the three numbers. Find the sum of the three numbers. ​

Answer 1

Answer:

there is nothing in this question

Answer 2

Given:

The sum of squares of three numbers is 398.

The sum of their products, taken two at a time, is 379.

To Find:

The sum of the three numbers. ​

Solution:

Let three numbers be x, y, and z.

As given,

x²+ y²+ z² = 398

xy + yz + xz = 379

According to the formula,

( x + y + z )² =  x²+ y²+ z² + 2 (xy + yz + xz)

( x + y + z )² = 398 + 2(379) = 398 + 758

( x + y + z )² = 1156

( x + y + z )² = √1156

x + y + z = 34

Hence, the sum of the three numbers is 34. ​