the sum of squares of two consecutire even natural numbers is 244 , find the numbers
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(n)^2 + (n+2)^2 = 244
n^2 + n^2 + 2^2 + 4n = 244
2n^2 +4n = 240
n^2 +2n = 120
n^2 + 2n -120 = 0
Solve by middle term split
To get
n^2 + 12n - 10n - 120 = 0
Then n = 10, ignore n= -12
Answer is n= 10 and n+2 = 10+2 = 12
n^2 + n^2 + 2^2 + 4n = 244
2n^2 +4n = 240
n^2 +2n = 120
n^2 + 2n -120 = 0
Solve by middle term split
To get
n^2 + 12n - 10n - 120 = 0
Then n = 10, ignore n= -12
Answer is n= 10 and n+2 = 10+2 = 12
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