The sum of Squares of two consecutive even natural number is 244. Find the number
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Answer:
Step-by-step explanation:
let the even natural consecutive numbers are x+1 and x+3
so,
[x+1]^2 + [x+3]^2 = 244
x^2+2x+1+x^2+9+6x = 244
2x^2+8x+10 = 244
2[x^2+4x+5] = 244
x^2+4x+5 = 122
x^2+4x+5-122 = 0
x^2+4x-117 = 0
x^2-9x+13x-117 = 0
x[x-9] +13[x-9] = 0
[x+13][x-9] = 0
x = 9 , -13
therefore the numbers are ; x+1 = 9+1 = 10
x+3 = 9+3=12
10 and 12
Answered by
24
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