the sum of squares of two consecutive even naturan no is 244,find the no's
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Answered by
2
let x-the first number
x+1-the second number
x^2+(x+2)^2 = 244
x^2+x^2+4x+4 = 244
2x^2+4x+4 = 244
2x^2+4x-240=0
by quadratic formula:
x=10 & -12
then,
if x = 10,x+2 = 12 ---answer
and
if x = -12, x+2 = -10 ----answer
x+1-the second number
x^2+(x+2)^2 = 244
x^2+x^2+4x+4 = 244
2x^2+4x+4 = 244
2x^2+4x-240=0
by quadratic formula:
x=10 & -12
then,
if x = 10,x+2 = 12 ---answer
and
if x = -12, x+2 = -10 ----answer
Answered by
0
Let the no. be x, x+2
then,
x + x + 2 =244
2x=244-2
2x=242
x=121.
then,
x + 2= 121 + 2 =123 ans.
then,
x + x + 2 =244
2x=244-2
2x=242
x=121.
then,
x + 2= 121 + 2 =123 ans.
subuhiali0:
ok
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