the sum of squares of two consecutive even positive is 13 times the first even integer find the integers
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Answer:
Step-by-step explanation:
let the integers be x and x+2(the integers are consecutive and even)
x^2 + (x+2)^2 = 13x
x^2 + x^2 + 4 + 4x = 13x
2x^2 + 4 - 11x = 0
2x^2 - 11x + 4= 0
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