Question

The sum of squares of two consecutive natural number is 224 find the number

Answer 1

let the no. be x, x+1
x^2+(x +1)^2=224
x^2+x^2+x+1=224
2x^2+x+1=224
2x^2+x=223
2x+x=

$\sqrt{223}$
3x=14.93
x=4.97

Answer 2

sorry I have no idea sorry