Question

the sum of squares of two consecutive natural numbers is 244; find the numbers.

Answer 1

Hello friend this is your answer..


The sum of the squares of two consecutive integers is 244. Find the two integers.
Sol'n:think it two consecutive even integers, not a consecutive integers
let x-the first number
x+1-the second number
x^2+(x+2)^2 = 244
x^2+x^2+4x+4 = 244
2x^2+4x+4 = 244
2x^2+4x-240=0
by quadratic formula:
x=10 & -12
then,
if x = 10,x+2 = 12 ---answer
and
if x = -12, x+2 = -10 ----answer

Hope it helps....