The sum of squares of two consecutive natural numbers is 244; find the numbers.
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The sum of squares of two “consecutive natural number” is 244, the numbers will be “12 and 10”.
Given:
Sum of squares of two consecutive natural number is 244.
Solution:
Let us consider the first number as x, then the second number will be x + 2
It is given that the sum of squares of two consecutive natural number is 244.
This can be written in equation as under:
⇒(x)²+(x+2)²=244
⇒x²+x²+4x+4=244
⇒2x²+4x=244−4
⇒2x²+4x=240
⇒2x²+4x−240=0
⇒2(x²+2x−120)=0
⇒(x²+2x−120)=0
⇒x(x+12)−10(x+12)=0
⇒(x−10)(x+12)=0
⇒x=10,−12
Thus, non be x= 12 & x = 10.
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