Question

#The sum of squares of two consecutive positive integers is 145. Find the integers. Let consecutive integers be x and (x+1). Given x^2+(x+1)2=145. Solving x^2+x^2+2x+1 =145 We get the quadratic equation as 2x^2+2x-144 = 0. Find the integers of the word problem stated above. answer this please!!!!!!

Answer 1

Answer:

-9, 8

Step-by-step explanation:

x^2+x-72=0

(x+9)(x-8) =0

x= -9,8

Answer 2

ANSWER

X=8

X+1=9

Explanation Step by Step