Question

The sum of squares of two natural numbers is 74 and the first number is three less than twice the second. Find the numbers

Answer 1

Answer:

5 and 7

Step-by-step explanation:

let us consider that the second no. is - x

now according to the question

2nd no. must be - (2x-3)

bcoz it is mentioned that first no. is 3 less than twice of another no.

Now

(x)²+(2x-3)²= 74

=> x²+ 4x²+9-12x = 74

=> 5x²-12x+9 = 74

X = 5

means first no. is 5 the second no. will be

2(5)-3 = 7

confirmation :-

(5)²+ (7)² = ?

25+49 = 74

means anwers is right