Question

The sum of squares of two numbers is 250
and difference of their squares is 88. Find
the two numbers ?
(1) 10, 12
(2) 8,14
(3) 7, 15
(4) None of these​

Answer 1

Step-by-step explanation:

2x2=338

x2=169

x=13

answer is d none of these

Answer 2

Answer:

Option 4 - None of these

Step-by-step explanation:

Let the numbers be a and b.

$a^{2} + b^{2} =250 \\ a^{2} - b^{2} =88$  

Adding both equations we get,

$2a^{2} =338$

$a^{2} =\frac{338}{2}$

$a^{2} =169$

$\\ \sqrt{a^{2} } =\sqrt{169}$

$a = 13$

$a^{2} - b^{2} =88$

$169 - b^{2} =88$

$b^{2} =169-88$

$b^{2} =81$

$\sqrt{b^{2} } =\sqrt{81}$

$b=9$

Therefore the numbers are 13 and 9.

Hope this helps.

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