Math, asked by vamshi01032009, 7 months ago

The sum of successor of 'n' and predecessor of 'n' is
a)n
b)n²
c)2n
d)2+n​

Answers

Answered by Anonymous
3

Answer:

2n

Step-by-step explanation:

Successor of n=n+1.

Predecessor of n=n−1.

∴ Sum of (n+1)+(n−1),

= 2n.

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