The sum of successor of 'n' and predecessor of 'n' is
a)n
b)n²
c)2n
d)2+n
Answers
Answered by
3
Answer:
2n
Step-by-step explanation:
Successor of n=n+1.
Predecessor of n=n−1.
∴ Sum of (n+1)+(n−1),
= 2n.
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