Question

the sum of successors of two numbers is 42 and the difference their predecessors is 12 find the numbers ​

Answer 1

Answer:

x=14,y=26

Step-by-step explanation:

let the numbers be x and y

successors of x and y is x+1 and y+1

the sum of successors of x and y is 42

predecessors of x and y is x-1 and y-1

the difference of predecessors is 12

now equations is.1. ( x+1 )+(y+1)=42

2. ( x-1) -(y-1)=12

solving both equations , we get -

x =14 , y=26

thank you

Answer 2

Answer:

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Step-by-step explanation:

Answer:

x=14,y=26

Step-by-step explanation:

let the numbers be x and y

successors of x and y is x+1 and y+1

the sum of successors of x and y is 42

predecessors of x and y is x-1 and y-1

the difference of predecessors is 12

now equations is.1. ( x+1 )+(y+1)=42

2. ( x-1) -(y-1)=12

solving both equations , we get -

x =14 , y=26

thank you

pls mark it as brain list