Question

The sum of surface areas of the two circular faces of a right circular cylinder is 166dm².the height of the cylinder is 42dm.Find its radius and volume.​

Answer 1

$here \: is \: your \: answer \: mate$

CORRECTION IN THE QUESTION::::::::

WE ONLY HAVE TO FIND THE VOLUME OF THE CYLINDER , RADIUS IS IMPRACTICAL TO BE FOUND IN THIS QUESTION.

GIVEN :::::::::

HEIGHT OF THE CYLINDER = 42DM

AREA OF ITS BASE +TOP = 166DM²

TO FIND ::::::

VOLUME OF THE CYLINDER

FORMULA USED ::::::

$\pi {r}^{2} h$

AND

$\pi {r}^{2}$

HOW TO FIND::::::

AR(TOP + BASE) = 166

$\pi {r}^{2} + \pi {r}^{2} = 166$

2 × 22/7 × r² = 166

r² = 166× 7/22 × 1/2

NOW,

WE HAVE TO FIND THE VOLUME OF THECYLINDER

WE KNOW THE FORMULA(MENTIONEDABOVE)

THEREFORE,

22/7 × r² × h = ?

22/7 × 166 × 7/22 × 1/2 × 42 =

166× 1/2 × 42 = 3486dm²

ANSWER ::::::::::

VOLUME OF CYLINDER = 3486dm²

HOPE IT HELPS YOU...PLEASE MARK AS THE BRAINLIEST....❤

Answer 2

Answer:volume of the cylinder......=3486dm sq.

poda chetta......unniyetta......