the sum of tearm of an ap is 5n2-3 find the sum of the tenth tearm
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Answer:
Putting n=1, 5n
2
−3n
=5−3=2
putting n=2, 5n
2
−3n
5×2
2
−3×2 =14
therefore 2nd term is 14−2=12
therefore A.P is 2,12,22.... and so on.
10th term =a+9d
=2+9×10
=2+90
=92
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