Question

The sum of tge ages of a son is 56 years.After four years‚the age of father will be three times‚that of the son.what is their ages?Solve by step by step​

Answer 1

Answer:

Age of son and father are 12 and 44 years respectively.

Step-by-step explanation:

Let age of son be x.

Age of father = 56 - x.

After 4 years,

Age of son = x + 4

Age of father = 60 - x

$60 - x = 3(x + 4) \\ = > 60 - x = 3x + 12 \\ = > 3x + x = 60 - 12 \\ = > 4x = 48 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > x = \frac{48}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > x = 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ age \: of \: father = 56 - x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 56 - 12 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 44 \: years$

Please mark this answer as brainliest

Answer 2

Given:

• The sum of tge ages of a son is 56 years.
• After four years‚the age of father will be three times‚that of the son.

To Find:

• Present ages

Solution:

Let the age of father be x

Age of son = (56 - x)

After four years,

• Age of Father = (x + 4)
• Age of son = (56 - x + 4)

According to Question,

➞ (56 - x + 4) = 3 (x + 4)

➞ 56 - x - 3x - 12 + 4 = 0

➞ 4x = 56 - 8

➞ 4x = 48

➞ x = 48/4

➞ x = 12 years

Hence,

• Son's age = 12 years
• Father's age = 56 - 12 = 44 years.

━━━━━━━━━━━━