Question

The sum of the 1st 45 terms of an A.P. is 3150.find it's 23rd term

Answer 1

Answer:

the answer is 70

Step-by-step explanation:

sum of first 45 terms=45{2a+(45-1)d}/2

3150=45(2a+44d)/2

3150/45=2(a+22d)/2

70=a+22d

a+(23-1)d=70

Therefore, 23rd term=70

Answer 2

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