Question

the sum of the 2 and the 7 terms of an arithmetic progression is 30 if its 15 term is 1 less than twice its 8th term find the arithmetic progression​

Answer 1

Hope it is helpful.....

Answer 2

Answer:

a2

Step-by-step explanation:

a2+a7==30

a+(n-1)d+a+(n-1)d=30

2a+1d+6d=30

2a+7d=30

2a8-a15=1

2a+14d-a-14d=1

a=1

now,

2a+7d=30

2+7d=30

7d=30-2

7d=28

d=4

AP is ...1,5,9,13.....