Question

the sum of the 2digit no. and the no. obtained be the reversing the order of ts digit is 99.if the digit differ by 3.find the no.?

Answer 1

Step-by-step explanation:

Let the 2 digits be x,y. respectively

2 digit number =10x+y

2 digit number obtained by ususing the digit =10y+x

∴10x+y+10y+x=99

⇒11x+11y=99

⇒x+y=9

x−y=3

On adding : 2x=12

                    x=6

putting x in ⟶(i)

6+y=9

y=3

∴ Number =10x+y=63

or , 10y+x=36.

Answer 2

Answer:

36

Step-by-step explanation:

Let the 2 digits be x,y. respectively

2 digit number =10x+y

2 digit number obtained by ususing the digit =10y+x

∴10x+y+10y+x=99

⇒11x+11y=99

⇒x+y=9

x−y=3

On adding : 2x=12

                    x=6

putting x in ⟶(i)

6+y=9

y=3

∴ Number =10x+y=63

or , 10y+x=36.