Question

the sum of the 3 numbers is 66. the second number is twice and the 3rd exceeds by 6. find the numbers

Answer 1

Answer:

The numbers are 15, 30 and 21.

Step-by-step explanation:

Let x be the first number. Then, by the given condition, the second number is 2x and the third number is x+6.

Now,

x + 2x + (x+6) = 66

=> 4x = 60

=> x = 15.

Hence, the first number = 15, the second = 2×15 = 30 amd the third = 15 + 6 = 21