The sum of the 3 terms of a arithematic sequence is 45 if the product of the first and 3rd terms exceeds the 2nd term by 41.find the arithematic sequence?
Answers
Answered by
0
let the terms be a,a+d,a+2d
a+a+d+a+2d=45
3a+3d=45
a+d=15
Given...a(a+2d)-(a+d)=41
a^2+2ad-a-d=41
kapilsaraswat781:
it is little bit confusing
Answered by
0
××××××××··,,,,,÷±≈≠∧∉ФФππΔβ∞∞∴ππππππππππππππππω
Similar questions