Question

the sum of the 3rd and 9th term of an ap is 10 and find a possible sum of the first 11 terms of the AP ​

Answer 1

Answer:

The third term t3 = a + 3d

The ninth term t9 = a + 8d

t3 + t9 = 2a + 10d = 8

Sum of first 11 terms of an AP is given by

⇒S11=112[2a+10d]⇒S11=112×8⇒S11=44

Step-by-step explanation:

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