Question

The sum of the 4 and 5 in terms of an AP is 24 and the sum of the 6 and 10 terms is 44. Find the first three terms of the AP.​

Answer 1

Answer:

this answer will help you

Answer 2

Answer:

2,34/7,54/7

Step-by-step explanation:

Given,

a4+a5=24

a6+a10=44

We know that, aN=a+(N-1)d

a4=a+3d,a5=a+4d,a6=a+5d,a10=a+9d

a+3d+a+4d=24,a+5d+a+9d=44

2a+7d=24---(1),2a+14d=44---(2)

Subtracting (1) from (2),We get,

7d=20

d=20/7

Substitute in (1), 2a+7(20/7)=24

2a+20=24

2a=4

a1=a=2(First term)

a2=a+d=2+20/7

a2=34/7(Second term)

a3=a+2d=2+2*20/7

a3=54/7(Third term)

Hope it helps you..