Question

The sum of the 4 and 8 term of an AP is 24 and
the sum of the 6 and 10" term is 44. Find the first
three terms of the AP​

Answer 1

Hope it helps you....

All the best...

Answer 2

Answer:

Step-by-step explanation:

nth term in AP=a+(n-1)*d

4th term=a+(4-1)*d=a+3d

8th term=a+(8-1)*d=a+7d

sum of 4th and 8th=24

a+3d+a+7d=24

2a+10d=24-----(1)

6th term=a+(6-1)d=a+5d

10th term=a+(10-1)d=a+9d

sum of 6th and 10th=44

2a+14d=44-----(2)

solving (1) and(2)

we get,

4d=20

d=5

now a=(44-70)/2=-26/2=-13

now first three terms

a,a+d,a+2d

-13,-13+5,-13+2*5

-13,-8,-3