Question

The sum of the 4 terms of an AP is 50. If largest term is four terms its smallest term then
find its four terms.​

Answer 1

Answer:

It is given to us that the sum of 4 terms is 50,

so let the 1st term be a,

then,

2nd term = a + d

3rd term = a + 2d

4th term = a + 3d

so,

a + (a + d) + (a + 2d) + (a + 3d) = 50

4a + 6d = 50

2 (2a + 3d)=50

2a + 3d = 25 ..... (eq.i)

now,

a + 3d = 4 a

3d = 3a

d = a .... (eq.ii)

putting d = a in eq.i,

2a + 3a =25

5a = 25

a = 5

now, from eq.ii,

a = d

so, d = 5

now,

A.P : a, a + d, a + 2d, a + 3d

so,

A.P : 5, 5 + 5, 5 + 2×5, 5 + 3×5

A.P : 5, 10, 15, 20

I hope you understood :)