the sum of the 4 th and 5 th term of AP is 24 and the sum of the 6 th and the 10 th term is 44 find the first three term of AP
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Step-by-step explanation:
use this for term = n/2{2a+(n-1)d}
2{2a+ 3d} + 2.5{2a + 4d} = 24 eq 1
3(2a +5d) + 5(2a+9d) = 44. eq 2
after solving that you get a and d them find
third term by 3/2( 2a + 2d)
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