Question

The sum of the 4 th and 8 th terms of AP is 24 and sum of the 6 th and 10 th term is 44 . find the first 3 terms of the AP

Answer 1

Step-by-step explanation:

From the question,

Let AP be a, a+d, a+2d ... a+(n-1)d.

So, 4th term + 8th term = 24

a+3d+a+7d=24

2a+10d=24

a+5d=12

Also, 6th term + 10th term = 44

a+5d+a+9d=44

2a+14d=44

a+7d=22

Now, a+5d=12 and a+7d=22

So, 12-5d=22-7d

7d-5d=22-12

2d=10

d=5

Hence, a=12-5d=12-5(5)=12-25=-13.

So, the AP is -13,-8,-3,2...

Thank you