Question

The sum of the 4 th term and the 8th of and ap 24 and the aul of the 6th twrm and 10th term and 44th fins the first three terms

Answer 1

Answer:

1st term is a = - 13

2nd term is a+d = -8

3rd term is a + 2d = -3

Step-by-step explanation:

AP : a,a+d,a+2d,.......

sum of 4th and 8th term of AP is 24

a + 3d + a + 7d = 24

2a + 10d = 24

a + 5d = 12 ----(1)

sum of 6th and 10th term of AP is 44

a +5d + a + 9d = 44

2a + 14d = 44

a + 7d = 22 ---(2)

subtract (1) -(2)

a + 5d - a - 7d = 12 - 22

-2d = -10

d = -10/-2 = 5

from equation 1

a = 12 - 5d = 12 - 5×5 = 12 - 25 = -13

a = -13, d = 5

1st term is a = - 13

2nd term is a+d = -13 + 5 = - 8

3rd term is a + 2d = -13 + 2×5

= -13 + 10

= -3