The sum of the 4th and 5th term of an AP is 24,sumof 6th term and 10th term is 34,FInd common Difference and first term.
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a4+a5=24
(a+3d)+(a+4d)=24
2a+7d=24....eq1
And a6+a10=34
(a+5d)+(a+9d)=34
2a+14d=34.....eq2
Substract eq1 from 2:
7d=10=> d=10/7
First term a=> 2a+7d=24
=> 2a+7(10/7)=24
=> 2a+10=24
=> a= 7 first term
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