Question

The sum of the 4th and 5th term of an AP is 24,sumof 6th term and 10th term is 34,FInd common Difference and first term.

Answer 1

a4+a5=24 (a+3d)+(a+4d)=24 2a+7d=24....eq1 And a6+a10=34 (a+5d)+(a+9d)=34 2a+14d=34.....eq2 Substract eq1 from 2: 7d=10=> d=10/7 First term a=> 2a+7d=24 => 2a+7(10/7)=24 => 2a+10=24 => a= 7 first term