Question

The sum of the 4th and 8 th term of an AP is 24 and the sum of the 6th and 10th term is 44. Find the first three terms of the AP​

Answer 1

4 term of AP=a+3d

8 term = a+7d

6term = a+5d

10 term = a+9d

4th term + 8 term = 24

a+3d+a+7d= 24

2a +10d=24—(I)

6th term + 10th term = 44

a+5d+a+9d=44

2a+14d=44—(ii)

subtract equ. (I) from (ii)

2a+14d=44

-(2a +10d=24)

= 4d=20

d=20/4

d=5

putting the value of d in equ. to find the value of a

2a+10d=24

2a+10(5) =24

2a+50=24

2a=24-50

2a= -26

a=26/2

a=13

first term is 13 and common difference is 5 so, three first term is -

13, 13+5, 13+2(5)

13,18,23