The sum of the 4th and 8th term of an ap is 24 and the sum of the 6th and 10 th term is 44.Find the first 3 term of the AP.
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Step-by-step explanation
⇒a+3d+a+7d=24
⇒2a+10d=24
⇒a+5d=12 …………(1)
⇒a+5d+a+9d=44
⇒2a+14d=44
⇒a+7d=22…………(2)
Equation (2) - Equation (1)
⇒-2d=-10
⇒d= 5
substitute value of d in eq 2
a+7*5=22
a+35=22
a=-13
AP= -13 , -8 , -3
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