Question

The sum of the 4th and 8th term of an AP is 24 and the sum of the 6th and 10th term is 44. Find the sum of 24 terms​

Answer 1

Step-by-step explanation:

Here,

a₄ = a + 3d

a₈ = a + 7d

Therefore,

a + 3d + a + 7d = 24

2a + 10d = 24

a + 5d = 12 [Equation 1st]

Again,

a₆ = a + 5d

a₁₀ = a + 9d

Therefore,

a + 5d + a + 9d = 44

2a + 14d = 44

a + 7d = 22 [Equation 2nd]

Solving Equation (1) and (2), we get:

d = 5 and a = -13

Therefore,

a₁ = a = -13

a₂ = a + d = -13 + 5 = -8

a₃ = a + 2d = -13 + 2 x 5 = -13 + 10 = -3

Hence this is the required result