The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44. Find the first three terms of the AP.
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Answer:
Step-by-step explanation:
A4=a+3d
A8=a+7d
And
A6=a+5d
A10=a+9d
Then
a+3d+a+7d=24
a+5d+a+9d=44
By solving we get
(1)-- 2a+10d=24
(2)--2a+14d=44
By elimination we want to do that
We get d=5
Sub d value in (1) then
We get a=-13 then do
A1=a=-13
A2=a+d=-13+(5)=-8
A3=a+2d=-13+2(5)=-13+10=-3
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