Question

the sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44. find the first three term of the AP
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Answer 1

Answer:

given :- sum of 4

th

and 8

th

term is 24.

a+3d+a+7d=24

2a+10d=24

a+5d=12.....(i)

sum of 6

th

and 10

th

term is 44.

a+5d+a+9d=44

12+a+9d=44......from (i)

a+9d=32

a+5d+4d=32

12+4d=32

d=5

a+25=12

a=−13

AP=−13,−8,−3,2,7,12.