Question

The sum of the 4th and 8th terms of an AP is 24, and the sum of 6th and 10th term AP is 44. Find the first three terms of the AP .
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Answer 1

Answer:

24+44

66answer...

Step-by-step explanation:

hope this helps you a lot..

Answer 2

Step-by-step explanation:

Let the first term be a and com. diff. be d.

nth term = a + (n - 1)d

In the question :

Case 1: 4th + 8th term is 24

=> (a + 3d) + (a + 7d) = 24

=> a + 5d = 12 ...(1)

Case 2: 6th + 10th term is 44

=> (a + 5d) + (a + 9d) = 44

=> a + 7d = 22 ...(2)

Subtracting (1) from (2), we get

=> (a + 7d) - (a + 5d) = 22 - 12

=> d = 5

Thus, in eqⁿ: a + 5(5) = 12 → a = - 13

Therefore, first three terms are:

a = - 13

a + d = -13 + 5 = -8

a + 2d = -13 + 5(2) = -3

First three terms are -13, -8, -3.