Question

The sum of the 4th and 8th terms of an ap is 24 and the sum of the 6th and 10th terms is 44 find the 1st two terms

Answer 1

Hey there !!

Given :-

→ a₄ + a₈ = 24.

→ a₆ + a₁₀ = 44.

To find :-

→ a₁ and a₂ .

Solution :-

We have,

→ a₄ + a₈ = 24 .

⇒ a + 3d + a + 7d = 24.

⇒ 2a + 10d + 24.

⇒ 2( a + 5d ) = 24.

⇒ a + 5d = 12.......(1).

And,

→ a₆ + a₁₀ = 44.

⇒ a + 5d + a + 9d = 44 .

⇒ 2a + 14d = 44.

⇒ 2( a + 7d ) = 44.

⇒ a + 7d = 22..........(2).

On substracting equation (1) and (2) , we get

a + 5d = 12

a + 7d = 22.

-  -      -

___________

⇒ - 2d = - 10.

∴ d = 5.

Put the value of d in equation (1) , we get

⇒ a + 5 × 5 = 12.

⇒ a + 25 = 12.

⇒ a = 12 - 25 .

⇒ a₁ = - 13 .

⇒ a₂ = a₁ + d = -13 + 5 = -8.

Hence, first two terms of AP is -13 and -8 .

THANKS

#BeBrainly.

Answer 2

$\underline{\bold{Answer:-}}$





Refer to the attachment above for your solution









$\textbf{Hope it helps!}$