Question

The sum of the 4th and the 8th terms of an
A.P. is 24 and the sum of the 6th and the 10th
terms of the same A.P. is 34. Find the first
three terms of the A.P.​

Answer 1

Answer:

a+3d+a+7d=24,a+5d+a+9d=34

Answer 2

a= -21/2

Explanation:

a+3d+a+7d=24

=> 2a+10d=24

=> a+5d=12 ....(1)

Now again

a+5d+a+9d=34

=> 2a+14d=34

=> a+7d=17. ....(2)

Now solve (1) and (2), to get a and d.

subtact (2) from (1)

we get , d= 9/2

and a = -21/2