Question

The sum of the 5th &6th terms of ap is 36& the sum of the 8th &9th terms is 48 find the first 3terms of an ap please help by sending picture?​

Answer 1

Step-by-step explanation:

a+4d+a+5d=36

2a+9d=36...............(1)

a+7d+a+8d=48

2a+15d=48.............(2)

subtracting eqn (1) from (2) , we get

6d=12

d=2

now , putting d=2 in eqn (1) , we get

2a+9×2=36

so , a=9

Now , according to question

Term 1 = a = 9

Term 2 = a+d = 11

Term 3 = a+2d = 13