The sum of the 5th and 7th terms of an AP is 52 and the 10th term is 46.Find the A.P.
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Answer:
the A.P is=1,6,11,16,21,26,31,36,41,46
Step-by-step explanation:
T5+T7=52
T10=46
nth term of an ap is = a+(n-1)d
T5+T7=a+(5-1)d+a+(7-1)d=52
2a+10d=52
a+5d=26 (equation 1)
T10=a+(10-1)d=a+9d
a+9d=46 (equation 2)
subtract equation 1 and 2
a+5d=26
a+9d=46
- - -
-4d=-20
d=5
substitute in equation 1
a+5*5=26
a+25=26
a=25-26
a=1
the ap is=1,6,11,16,21,26,31,36,41,46
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