The sum of the 5th and 9th term of AP is 1530. if its 25th term is three times its 8th term. find the AP.
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Step-by-step explanation:
nth term tn=a+(n−1)d
a= First term
d= Common difference
n= number of terms
tn=nth term
Given
T5+T9=30
a+4d+a+8d=30
2a+12d=30
a+6d=15
a=−6d+15
now
T25=3T8
a+24d=3(a+7d)
24d−21d=3a−a
3d=2a
3d=2(6d−15)
15d=30
d=2
a=15−6×2
a=3
The AP is 3,5,7,9.........
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