The sum of the 5th and the 7th terms of an AP is 40 and their product is 391. Find the
value of the common difference.
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Answered by
0
Let the first term be a and common difference is d,
a+(7−1)d=40
a+6d=40
Now sum of 13 term is
2
13
(2a+12d)=
2
13
.2.40=520
Answered by
0
Answer:
ok i have proof
Step-by-step explanation:
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