The sum of the a two digit number is 12 if the new number formed by reversing its digits is greater than the original number by 54 find the original number
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Let the tens place be x
Let the ones place be y
According to the condition
x + y = 12
Since by reversing
According to the condition
10y + x = (10x + y) + 54
10y + x = 10x + y + 54
Since, x + y = 12
Therefore x = 12 - y
Substituting x = 12 - y in above equation
Therefore 10y +x = 10x + y + 54
....by solving
9x - 9y = -54 [by substituting]
9(12 - y) -9y = -54
....by solving
y = 9
Then after ward substitute y = 9 in x + y = 12
....by solving
x = 3
Done!
Let the ones place be y
According to the condition
x + y = 12
Since by reversing
According to the condition
10y + x = (10x + y) + 54
10y + x = 10x + y + 54
Since, x + y = 12
Therefore x = 12 - y
Substituting x = 12 - y in above equation
Therefore 10y +x = 10x + y + 54
....by solving
9x - 9y = -54 [by substituting]
9(12 - y) -9y = -54
....by solving
y = 9
Then after ward substitute y = 9 in x + y = 12
....by solving
x = 3
Done!
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